Can anyone tell me if my attempt is correct?
gcd (a, a + b) = gcd (b, a + b) = gcd (a, b) = 1.
∴, gcd (a + b, ab) = 1.
Asked
Active
Viewed 298 times
0
-
I think it's correct. – Michael Rozenberg Oct 21 '17 at 10:07
-
Compare $\operatorname{gcd}(ab,a+b)=1$ if $a$ and $b$ are relatively prime. – Martin R Oct 21 '17 at 10:10
-
I don't understand how is it that you deduce something about $\operatorname{gcd}(a+b,ab)$ from three statements in which $ab$ does not appear. – José Carlos Santos Oct 21 '17 at 10:27