Drawer probability problem

Question

A chest of drawers has 3 drawers. Each drawer has 2 boxes. The boxes of one drawer contain a silver coin in each respectively, the boxes of another a gold coin in each box, and the boxes of the third drawer a gold and a silver coin, respectively. A drawer is selected at random and a box from the drawer is selected at random and opened. The coin is found to be silver. What is the probability that the coin in the other box is gold?

I got 0.5.

And yes, you are equally likely to select any particular drawer, but in each of those drawers there is a different probability for selecting the box containing a silver coin. Given that you did select a silver coin, you are most likely to have selected the drawer containing the most silver coins. — Graham Kemp, Oct 10 '17 at 00:51
Very similar problem. Following the links, here is essentially the problem you describe. — JMoravitz, Oct 10 '17 at 00:53
Don't be a jerk whoever you are doing the downvoting. He's obviously new here - cut him some slack! — , Oct 10 '17 at 00:57

score 0 · Answer 1 · answered Oct 10 '17 at 00:55

Each of the boxes was selected without bias (equal probability). Three of these coins are silver; two of which share the same drawer with a silver coin (each other, in fact), while the third is paired with a gold coin.

Given that you did select one of these three silver coins, what then is the probability that it was the one paired with a gold coin?

Drawer probability problem

1 Answers1