How many fields are there (Up to isomorphism) with exactly 6 elements? In case of Group of order 6.. number of group( up to isomorphism )is 2..but what is it in case of field?
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0............... – Randall Sep 05 '17 at 15:35
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1Also, please do some research before posting. The second google hit for "finite field order" is the question I linked to above, and the first hit is a Wikipedia article that cites the exact same result.... – Sep 05 '17 at 15:38
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@Jyrki Lahtonen ♦ ; why my flags does not count ? I have raised too many flags but it's about a week none of them has been counted, what's wrong with my account? – Davood Sep 05 '17 at 15:51
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I don't know @Famke. The last one I see in your flagging history is dated August 26. I will check with the other mods. May be they know something I don't? – Jyrki Lahtonen Sep 05 '17 at 16:04
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@Famke: A piece of news from a fellow mod. A user with 3k rep no longer casts close flags. They are automatically converted to votes to close. – Jyrki Lahtonen Sep 05 '17 at 17:55
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The order of a finite field must be a power of a prime, so there are no fields with $6=2\times3$ elements.
Kenny Lau
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1You might want to add that all finite fields with given order are isomorphic. – Bernard Sep 05 '17 at 15:37