Let a belong to the set of (Rationals - Integers)
How would you prove the following:
a squared belongs to the set of (Rationals - Integers)
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2The body of the question doesn't match the title. Which one are you asking? In case it matters, remember that $,i^2=-1,$, and $\big(\sqrt{2}\big)^2=2$. – dxiv Aug 30 '17 at 22:42
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Sorry I meant set of Complex minus set of Integers – Aug 30 '17 at 22:43
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1$i^2=-1$ your statement is false. – hamam_Abdallah Aug 30 '17 at 22:46
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Ah yes of course. I'm going to update the question to be irrational set minus integer. – Aug 30 '17 at 22:49
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If the dupes don't answer your question then please clarify why and we can reopen the question. – Bill Dubuque Aug 30 '17 at 23:01