Prove that for every integer $n \geq 0$, the number $4^{2n+1}+3^{n+2}$ is a multiple of 13.
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But what did you try? – Parcly Taxel Aug 19 '17 at 14:31
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See this answer for a detailed explanation of the arithmetical essence of the induction. – Bill Dubuque Aug 19 '17 at 14:49
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HINT: we have $$4^{2n+1}+3^{n+2}=16^n\cdot 4+3^n\cdot 9\equiv 3^n\cdot 4+3^n\cdot 9\equiv 3^n\cdot 13$$

Dr. Sonnhard Graubner
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