Limit $\lim_{x\to0}\frac{1-cos(x)}{x^2}$

Question

Is it possible to find the following limit without applying L'Hopital's Rule, but only with some transformations? $$\lim_{x\to0}\frac{1-cos(x)}{x^2}$$

Answer 1

Hint: write $$\frac{(1-\cos(x))(1+\cos(x))}{x^2(1+\cos(x))}$$