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The series:

$$\sum_{n=1}^{\infty}\frac{3^n+(-2)^n}{n}(x+1)^n$$

I just do not know where to start here, I trues to substitute $t=x+1$ but it did not help much

M.Mass
  • 2,672

1 Answers1

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HINT:

$$\frac{3^n+(-2)^n}{n}(x+1)^n=\dfrac{\{3(x+1)\}^n}n+\dfrac{\{-2(x+1)\}^n}n$$

As $\ln(1+x)=-\sum_{r=0}^\infty\dfrac{(-x)^r}r$ is convergent for $-1<x\le1$

we can use Taylor series for $\log(1+x)$ and its convergence OR What is the correct radius of convergence for $\ln(1+x)$?