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Something I'm reading says that for a compact connected complex Lie group $G$, the kernel of $\exp:T_e(G) \to G$ is a lattice $\Lambda$ in $T_e(G)$, and $\exp$ is surjective, so $G \simeq T_e(G)/\Lambda$. What is the story for real compact connected Lie groups? Looking at the classification of compact Lie groups, get things besides tori, e.g. $SO(n)$ and $SU(n)$. In these cases, is $\exp$ injective, surjective, or is the kernel a lattice and is the image a maximal torus?

usr0192
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  • Have you tried looking in the standard textbooks on this subject or even googling? This is a question that comes up extremely often, even in this site. – Mariano Suárez-Álvarez Jun 03 '17 at 16:39
  • I apologize! I didn't look it up myself, because I'm just experimenting with if asking questions on mathstackexchange can help me as I read one thing. I know i need to learn the fundamentals of Lie groups so again I apologize – usr0192 Jun 03 '17 at 16:48
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    The map $\exp$ is not a homomorphism, unless G is abelian, so knowing its "kernel" is not very useful. I suggest you work out the case of G=SO(3). – Moishe Kohan Jun 03 '17 at 17:18
  • https://math.stackexchange.com/questions/1089636/exponential-map-is-surjective-for-compact-connected-lie-group – Moishe Kohan Jun 03 '17 at 17:20

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