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$$\sum_{\ell=k}^n \binom{\ell}{k} = \binom{n+1}{k+1}$$

Can someone explain how we got that equation? Expanding it we get

$$\binom{k}{k} + \binom{k+1}{k} + \binom{k+2}{k} + .....+ \binom{n}{k}$$

but how does that add up to $$\binom{n+1}{k+1}$$

Jaideep Khare
  • 19,293

1 Answers1

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Hint : Rewrite $$\binom{k}{k} =\binom{k+1}{k+1}$$

And now use the identity $$\binom{k}{r}+\binom{k}{r+1}=\binom{k+1}{r+1}$$

Jaideep Khare
  • 19,293