Find an explicit formula for the recursive sequence $a(n+1)=3a(n)-8$ where $a(1)=4$.
Is the formula an=4 and how to prove it by induction I dont really know how to prove it using induction if this were the right answer
Find an explicit formula for the recursive sequence $a(n+1)=3a(n)-8$ where $a(1)=4$.
Is the formula an=4 and how to prove it by induction I dont really know how to prove it using induction if this were the right answer
Hint (telescoping instead of induction): the recursion formula can be written as:
$$a_{n+1}-4=3(a_{n}-4)=3^2(a_{n-1}-4)=\cdots=3^{n}(a_1-4)$$
Let $P(n)$ be the statement $a(n) = 4$. Given $a(1) = 4$ and $P(1)$ is true.
Assume $a(k) = 4$ for some $k\in\mathbb N$. Then $$a(k+1) = 3a(k) - 8 = 12 - 8 = 4$$
So $P(k+1)$ is true.