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I don't know if that property is true for infinite cardinal numbers, but i think is true because the sum of cardinal numbers are a cardinal number and the product of cardinal numbers are conmutative. I'm right?

sango
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  • See this https://math.stackexchange.com/questions/131212/overview-of-basic-results-on-cardinal-arithmetic – Ahmed S. Attaalla May 10 '17 at 02:04
  • You are right, for cardinal numbers, multiplication is commutative. This is easily seen looking at the map $A\times B\to B\times A$, $(a,b)\to (b,a)$ which you can prove is bijective – Maxime Ramzi May 10 '17 at 07:40

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