How to show convergence of : $$\lim_{n \to \infty}\sum_{k=1}^{n} \frac{n+k}{(n^2+k^2)}$$
Asked
Active
Viewed 84 times
0
-
Hi. Tried helping with the typesetting, please let me know if I got it wrong. – mathreadler Apr 23 '17 at 09:31
-
Use the idea of https://math.stackexchange.com/questions/469885/the-limit-of-a-sum-sum-k-1n-fracnn2k2/469886#469886 – lab bhattacharjee Apr 23 '17 at 09:32
-
1Maybe there should be a limit $n \to \infty$? – mathreadler Apr 23 '17 at 09:37
-
Thank you,I'll try solving it that way,the problem asks me to prove that this series converges – Lola Apr 23 '17 at 09:38
-
1Do you mean the series with general term this sum, or the sequence defined by this sum? – Bernard Apr 23 '17 at 09:58
-
Indeed, which series? – Did Apr 23 '17 at 10:07
1 Answers
4
We will try to evaluate it using limit of a sum which will eventually prove that it converges.
$$\lim_{n \to \infty} \sum_{k=1}^n \frac{(n+k)\frac{1}{n^2}}{(n^2+k^2)\frac{1}{n^2}}$$ $$\lim_{n \to \infty} \sum_{k=1}^n \frac{(1+\frac{k}{n})\frac{1}{n}}{(1+\frac{k^2}{n^2})}$$ Converting it into a definite integral. $$\int_{0}^1 \frac{1+x}{1+x^2} dx$$ $$\int_{0}^1 \left(\frac{1}{1+x^2}+\frac{x}{1+x^2}\right) dx$$ This can be easily evaluated.
The result comes out to be $\frac{\pi}{4} + \frac{1}{2}ln2$
Which proves that it the given sum converges.

Aman Sharma
- 511