Possible Duplicate:
How can I evaluate $\sum_{n=1}^\infty \frac{2n}{3^{n+1}}$
I have an infinite series like so:
$$\sum_{i=0}^\infty (i+1)x^i$$
or basically
$$ 1 + 2x + 3x^2 + 4x^3 +... $$
Is there a way to simplify this? If so, how?
Possible Duplicate:
How can I evaluate $\sum_{n=1}^\infty \frac{2n}{3^{n+1}}$
I have an infinite series like so:
$$\sum_{i=0}^\infty (i+1)x^i$$
or basically
$$ 1 + 2x + 3x^2 + 4x^3 +... $$
Is there a way to simplify this? If so, how?