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Proving $\int_0^{\infty} \mathrm{e}^{-x}\log(x)dx=-\gamma$
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Mar 29 '17 at 11:34
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Mar 29 '17 at 11:34
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How can I prove that
$$\int_0^{\infty} \mathrm{e}^{-x}\log(x)dx=-\gamma$$
integration
asked Mar 29 '17 at 11:34
vito
1,893
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21
What is your definition of $\gamma$? Or, tell us something you know about $\gamma$.
–
mickep
Mar 29 '17 at 11:35
2
http://math.stackexchange.com/questions/112304/showing-that-gamma-int-0-infty-e-t-log-t-dt-where-gamma-is-t
–
Zubzub
Mar 29 '17 at 11:39
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