Can anyone help me with it: Using the central limit theorem for suitable Poisson random variables, prove that $$ \lim_{n\to\infty} e^{-n} \sum_{k=0}^{n} \frac{n^k}{k!}=1/2$$ Thanks!
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This question has been asked and answered countless times. – Lucian Dec 07 '15 at 21:50
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Hint: A Poisson$(n)$ random variable can be represented as the sum of $n$ i.i.d. Poisson$(1)$ rv's.

Shai Covo
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1@kira: Find a random variable $X$ for which it holds ${\rm P}(X=n) = \sum\nolimits_{k = 0}^n {\frac{{e^{ - n} n^k }}{{k!}}} $. – Shai Covo Feb 14 '11 at 10:11