0

Possible Duplicate:
Series converges implies $\lim{n a_n} = 0$

Someone can help me? If $(a_n)$ is a decreasing sequence and $\sum a_n$ converges. Then $\lim {(n.a_n)} = 0$.

I don't have idea how to solve this.

Community
  • 1
jon jones
  • 1,178

1 Answers1

1

By the Cauchy condensation test

$$\sum 2^m a_{2^m} < \infty$$

thus

$$\lim_n 2^m a_{2^m} =0$$

Now, for each $n$ chose some $m$ so that $2^m \leq n < 2^{m+1}$ and use

$$a_{2^m} \geq a_n \geq a_{2^{m+1}}$$

N. S.
  • 132,525