Goal: calculate the length of a cylindrical roll of tape given the thickness of the tape, the internal and external diameter of the roll.
Firstly, I considered the roll of tape to be a bunch of concentric "circles" rather than a spiral.
Let
- $L=$ length of the tape
- $t=$ thickness of the tape
- $d-2t=$ internal diameter (diameter of the cardboard in the middle)
- $D=$ external diameter (diameter of the largest circle)
- $\alpha= \frac{D-(d-2t)}{2t}$ (the total number of circles of tape)
Then,
$$L=\sum_{i=0}^{\alpha-1} \pi(d+2it)$$
$$=\sum_{i=0}^{\alpha-1} \pi d + \sum_{i=1}^{\alpha-1} 2\pi it$$
$$=\alpha \pi d + \alpha (\alpha -1) \pi t$$
$$=\alpha \pi [d + (\alpha -1)t]$$
I have tested this formula for a few different values of $\alpha$, $d$ and $t$ and it seems to give the correct answer.
However, a roll of tape is not a bunch of concentric circles.
Is there any way to calculate the exact length of tape given these parameters?
Furthermore, how effective would using the formula above be?