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How to prove $\pi^3<3^\pi$ without using explicit value of $\pi$? In the following link I proposed similar problem and got extremely amazing explanations which uses pure geometrical ideas : How to prove: $2^\frac{3}{2}<\pi$ without writing the explicit values of $\sqrt{2}$ and $\pi$

Here too I am thinking some similar kind of idea (not involving calculus) but not getting any. Can there also be something like that?

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Take the logarithm. Divide each side by $3 \pi$. Notice the question becomes:

$$ \frac{\ln \pi}{\pi} < \frac{ \ln 3}{3}$$

However, the derivative of $ f(x)=\frac{\ln x}{x}$ is $$f'(x)=\frac{1-\ln x}{x^2}$$ From the product rule. So the fucntion $f(x)=\frac{\ln x}{x}$ is decreasing if $x>e$ as $f'(x)<0$. The result follows as. $$\pi >3>e$$As seen here, here and here.

S.C.B.
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