Can someone help with these kind of questions
Find the number of integral solution of the following equation:
$$|x|+|y|+|z|=5$$
Can someone help with these kind of questions
Find the number of integral solution of the following equation:
$$|x|+|y|+|z|=5$$
Hints:
$x$ and $y$ can take any the integer values $0,\pm1,\pm2,\pm3,\pm4,\pm5$; they can't take any other values (why not?). The value of $|z|$ is then determined by those of $x$ and $y$; as $z$ also must be one of the integer values listed, you must have $|x|+|y|\le5$. If $|x|+|y|=5$, then $z=0$, otherwise $z$ has two values, one positive and one negative.
Using these hints, can you make a start?
This is an application of the stars-and-bars theorem.
Check this out : How to use stars and bars (combinatorics)
In this case, your problem is asking for the number of non-negative integral solutions to the equation.
$$ x+y+z=5 $$ The answer will be $\binom{5+3-1}{5}=21$