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How can we write $$x^{15 } +1$$ as a product of four factors.

I can only discern one thing about this, that $x^{3} +1$,$x^{5 } +1$ and $x^{15 } +1$ are going to be the factors. But I am unable to move ahead.

Harsh Sharma
  • 2,369

1 Answers1

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There just so happens to be this wonderful online calculator known as WolframAlpha, and upon putting your problem in, we find

$$x^{15}+1=(x+1)(x^2-x+1)(x^4-x^3+x^2-x+1)(x^8+x^7-x^5-x^4-x^3+x+1)$$

Particularly, notice that

$$x^3+1=(x+1)(x^2-x+1)$$

$$x^5+1=(x+1)(x^4-x^3+x^2-x+1)$$