Why does $1+2+\dots+2003=\dfrac{2004\cdot2003}2$?
Sorry if this is missing context; not really much to add...
Why does $1+2+\dots+2003=\dfrac{2004\cdot2003}2$?
Sorry if this is missing context; not really much to add...
$$\begin{array}{ccc} S&=&1&+&2&+&3&+&\ldots&+&2001&+&2002&+&2003\\ S&=&2003&+&2002&+&2001&+&\ldots&+&3&+&2&+&1\\ \hline 2S&=&2004&+&2004&+&2004&+&\ldots&+&2004&+&2004&+&2004 \end{array}$$
There are $2003$ columns, so $2S=2003\cdot2004$, and therefore $S=\dfrac{2003\cdot2004}2$.
By symmetry, the numbers are all centered around $\frac{n+1}{2}$, and there are $n$ of them.
https://en.wikipedia.org/wiki/Arithmetic_progression
– duanduan Dec 24 '16 at 23:28