Let $A$ be a symmetrical $2x2$ matrix. Given the equations
$$A*v_1=4*v_1$$
$$A*v_2=-v_2$$
Determine the scalar product $v_1*v_2$
Any hints?
Let $A$ be a symmetrical $2x2$ matrix. Given the equations
$$A*v_1=4*v_1$$
$$A*v_2=-v_2$$
Determine the scalar product $v_1*v_2$
Any hints?
It can be seen that $v_1$ and $v_2$ are two Eigenvectors corresponding to two different Eigenvalues ($4$ and $-1$) of $A$. Eigenvectors of real symmetric matrices are orthogonal.
Therefore $<v_1,v_2>=0$.
For generalized proof see: Eigenvectors of real symmetric matrices are orthogonal