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How can i prove this:

1. To every finite field K there exists a positive integer m sucht that m*a = a + a + ... + a ( a times ) = 0 for every a in K.

  1. The smallest positive integer m > 0 in 1. is a prime number.

2 Answers2

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Note that in a finite field $(F,+,.)$ ,$(F,+)$ is a finite group with zero element $0_F$.

In a finite group every element has finite order .Hence for each $a\in F$ there exists $n\in \Bbb N$ such that $n.a=0$

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Every field contains $1$ and $0$ by definition. The characteristic of a finite field must be a prime number, see here. Then $1+1\cdots +1=0, i.e., p\cdot 1=0$. Hence $p\cdot a=0$.

Dietrich Burde
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