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Given the congruence $x^3 \equiv a \pmod p$, where $p \geq 5$ is a prime and $\gcd(a,p)=1$, prove the following:

  • If $p \equiv1 \pmod 6$, then the congruence has either no solutions or three incongruent solutions modulo $p$
  • If $p \equiv5 \pmod 6$, then the congruence has a unique solution modulo $p$

Help me...

I don't know what I learn because Prof teaches so quickly.

So I need your help to organize my thoughts.

barak manos
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