Given the congruence $x^3 \equiv a \pmod p$, where $p \geq 5$ is a prime and $\gcd(a,p)=1$, prove the following:
- If $p \equiv1 \pmod 6$, then the congruence has either no solutions or three incongruent solutions modulo $p$
- If $p \equiv5 \pmod 6$, then the congruence has a unique solution modulo $p$
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