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Prove the following statement using a technique (contrapositive or contradiction)

If $x^2$ is prime, then $x$ is not a positive integer

My attempt: suppose $X$ is positive integer for further I can't get any idea any one help.

Davide Giraudo
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1 Answers1

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Hint: obviously $$x|x^2.$$ But $x^2$ is prime, thus its only (integer) divisors are $1$ and $x^2$. Conclude

b00n heT
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