Prove the following statement using a technique (contrapositive or contradiction)
If $x^2$ is prime, then $x$ is not a positive integer
My attempt: suppose $X$ is positive integer for further I can't get any idea any one help.
Prove the following statement using a technique (contrapositive or contradiction)
If $x^2$ is prime, then $x$ is not a positive integer
My attempt: suppose $X$ is positive integer for further I can't get any idea any one help.
Hint: obviously $$x|x^2.$$ But $x^2$ is prime, thus its only (integer) divisors are $1$ and $x^2$. Conclude