Argument problem

Question

What would be the argument of $i^i$? What are the possible ways to find it out?

score 2 · Answer 1 · answered Oct 05 '16 at 15:27

2

$i^i = e^{i\ln i} = e^{i\cdot i\pi/2} = e^{-\pi/2}$, so the argument is $0$.

answered Oct 05 '16 at 15:27

Anon

Great!! I really liked your answer. – Zlatan Oct 05 '16 at 15:28
1

Isn't it shorter to start from $i=\mathrm e^{i\tfrac\pi2}$? – Bernard Oct 05 '16 at 16:42

1 Answers1