Consider the envelope paradox problem:
There are two envelopes both of which contain some money. One envelope contains twice the amount of the other (but other than that, you do not know how much is in them). You select one of the envelopes randomly and see the amount of money inside.
You can opt to either keep the money in this envelope, or switch envelopes, which do you choose?
A (false) argument for switching envelopes:
Let the amount of money in the envelope you selected be $X$.
There is a $50\%$ chance that the envelope with more money is selected, and a $50\%$ chance that the envelope with less money is selected.
Therefore, there is a $50\%$ chance that there is $0.5X$ in the other envelope, and a $50\%$ chance that there is $2X$ in the other envelope.
So the expected payout for switching is ${2X + 0.5X\over2} = 1.25X$ which is better than the payout of $X$ for not switching.
Therefore you should switch.
This argument is wrong... where exactly does it fall?