Question
What is the corresponding Euler-Lagrange equation that minimizes the energy
$$E[u] = \frac{1}{2}\int_{\Omega} \|\nabla^k u \|^2 \> dx$$
where $\Omega \subseteq \mathbb{R}^n$ and $u: \Omega \mapsto \mathbb{R}$.
Conjecture $$\Delta^{k} u = 0$$
Background
For the standard Dirichlet Energy
$$E[u] = \frac{1}{2}\int_{\Omega} \|\nabla u \|^2 \> dV$$
we can prove that harmonic functions minimize this energy. A standard way to do this is to assume we have a function $w$ such that $\Delta w = 0$ for $x \in \Omega$. This means
$$\int_\Omega \Delta w(w-u) \> dx = 0$$ $$\int_\Omega \nabla u \cdot \nabla w \> dx - \int_\Omega \|\nabla w\|^2 \> dx = 0$$ $$\frac{1}{2} \int_\Omega \|\nabla u\|^2 + \|\nabla w\|^2 \> dx - \int_\Omega \|\nabla w\|^2 \> dx \ge 0$$ $$\frac{1}{2} \int_\Omega \|\nabla u\|^2 \ge \frac{1}{2} \int_\Omega \|\nabla w\|^2 \> dx$$
Since we didn't lose generality, this argument works for any choice of $u$. I suspect a similar technique should show the more general version, but I haven't been able to work out the identities.
The reason I am interested is this more general energy can be used to enforce more continuity at the handles of a mesh deformation. I'm going to keep looking into this and maybe post my own answer if no one beats me to it.