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On the section about the Hom sets of modules, Hungerford has an exercise that asks to show that $$\operatorname{Hom}(\mathbb{Z}_m, \mathbb{Z}_n) \cong \mathbb{Z}_{(m,n)}$$ and then in the next exercise he has

If $A,B$ are abelian groups and $m,n$ integers such that $mA = 0 = nB$, then every element of $\operatorname{Hom}(A,B)$ has order dividing $(m,n)$.

What does $(m,n)$ mean in these contexts?

Anfänger
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1 Answers1

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It means the greatest common divisor of $m$ and $n$.