if $a,b$ are natural numbers such that $(1+ab)|(a^2+b^2).$ then $\frac{a^2+b^2}{1+ab}$ is perfect square.please provide some hint.i have tried ,but donot know from where to start
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This is an example in wikipedia's article on Vieta jumping. – Arthur Jul 25 '16 at 12:31
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See this answer. – Bill Dubuque Jul 25 '16 at 21:06