Let $G$ be a group with $ord(G)=319$. Proove that $G$ is a cyclic group.
Answer: $ord(G)=319=11*29=n$, the Euler's totient function gives $\phi(n)=\phi(11*29)=\phi(11)*\phi(29)=10*28$. Since $gcd(319,280)=1$, $G$ is a cyclic group.
[Related:Answer from Nicky Hekster]
On the other hand , you can reach the result using that : Let $p$ and $q$ be primes such that $p>q$. If $q\equiv 1\mod p$, then every group of order $pq$ is isomorphic to the cyclic group $\Bbb Z/pq\Bbb Z$. (see Algebra by chapter III, proposition 6.1)
– carlos arturo Hurtado Jul 20 '16 at 17:30