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Let $N_1$ and $N_2$ be normal subgroups of G so that $N_1$ and $N_2$ are isomorphic. Is it true that then also $G/N_1$ is isomorphic to $G/N_2$?

Bahbi
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2 Answers2

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No. Let $N_1= 3 \mathbb{Z}$, $N_2 =4 \mathbb{Z}$. Both are normal subgroups of the additive group $\mathbb{Z}$. They are isomorphic via $f: 3x \mapsto 4x$. However, $\mathbb{Z}/3 \mathbb{Z}$ is not isomorphic to $\mathbb{Z}/ 4 \mathbb{Z}$ since these are both finite groups with a different number of elements, hence no bijection exists between them.

M10687
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No. Consider $G=Z_2\times Z_4$. This is abelians so all subgroups are normal. Try quotienting by some of the copies of $Z_2$ you can find in this group.

J.G
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