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Why intersection of two normal subgroups is trivial ?

I know this is simple but I cant get it. $|G|=11^{2}13^{2}$

$H$ and $K$ are $11$ and $13$ Sylow normal subgroups respectively .
Then why must be $H\cap K=e$ ? I am stuck on it for an hour or so.

Jean Marie
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kadir
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1 Answers1

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HINT

Every element of $H$ have order dividing $11$ and every element of $K$ have order dividing $13$.

$H \cap K$ is a subgroup of both. What can you say about the order of elements of subgroups?

Fredrik Meyer
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