Let $l$ be an odd prime number and $\zeta$ be a primitive $l$-th root of unity in $\mathbb{C}$. Let $K = \mathbb{Q}(\zeta)$. Let $A$ be the ring of algebraic integers in $K$. Let $G$ be the Galois group of $\mathbb{Q}(\zeta)/\mathbb{Q}$. $G$ is isomorphic to $(\mathbb{Z}/l\mathbb{Z})^*$. Hence $G$ is a cyclic group of order $l - 1$. Let $f = (l - 1)/2$. There exists a unique subgroup $G_f$ of $G$ whose order is $f$. Let $K_f$ be the fixed subfield of $K$ by $G_f$. $K_f$ is a unique quadratic subfield of $K$. Let $d$ be the discriminant of $K_f$.
My question: Is the following proposition true? If yes, how would you prove this?
Proposition
(1) If $l \equiv 1$ (mod 4), then $d = l$.
(2) If $l \equiv -1$ (mod 4), then $d = -l$.
Remark I think, together with this, we can get the quadratic reciprocity law.