I have studied for about 250 questions and there are many questions i can't take.. i considered but i don't know how to start... how can i solve this? In second question, there even hint..
Well im so glad if you tell me how to solve
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2For the second one, note that $gcd(a,b)=1$ implies that there exist $x,y$ integers such that $xa+yb=1$, implying $xam+ybm=m$. So, since $d\mid am$ and $d\mid bm$, you know that... – JMoravitz Apr 17 '16 at 19:56
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It is better not to put two unrelated questions together. Ask them as separate questions. – almagest Apr 17 '16 at 20:25
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For the first one you can prove that ever number is a multiple of 9999...999 – N.S.JOHN Apr 18 '16 at 13:46