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For a finite set $X$, we write $\sum X$ to be the sum of all the numbers in $X$. Suppose we have a set $S \subseteq \mathbb{R}$ such that $-100\le \sum X \le 100$ for all finite subsets $X \subseteq S$. How to show that $S$ is countable?

I do not really know where to begin. Hints would be nice. Thank you!

Andrew
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2 Answers2

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For each $n\in\mathbb N$ consider the sets $$ S\cap(-\infty,-1/n) \quad\text{and}\quad S\cap(1/n,\infty) $$ There are countably many of these sets, and their union is $S\setminus\{0\}$. How large can each of them be?

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This is strongly related to The sum of an uncountable number of positive numbers. Using this you know that all but countably many elements of S are 0. Since 0 appears at most once you are done.