Why are natural logs not calculated by hand often? Is it too difficult to get a accurate answer without a calculator?
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1It's pretty annoying. You can get okay accuracy (maybe a few sig figs) by memorizing a few of them and using tricks. – Qiaochu Yuan Mar 03 '16 at 22:13
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1More discussion here: http://math.stackexchange.com/q/820094/215011 – grand_chat Mar 03 '16 at 22:18
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1Extremely hard! and !!!!VERY!!!! tedious! – fleablood Mar 03 '16 at 22:36
1 Answers
Remember how your were taught how to add, subtract, multiply and divide when you were a young child? These are very easy to do by hand. It's very hard to do anything else, e.g. square roots, cube roots, trigonometric functions and logarithms are very hard to do by hand.
It is possible to do, but you need to break them up into the four basic operations. It's possible to write logs as addition and multiplication, as follows:
A series expansion is the best way to calculate approximate values.
For example, for some values of $x$, the Taylor Series expansion is $$\ln\left(\frac{1}{1-x}\right) = x + \frac{1}{2}x^2+\frac{1}{3}x^3+\frac{1}{4}x^4+\cdots+\frac{1}{k}x^k+\cdots$$
If you want to approximate $\ln 2$, then substitute $x=\frac{1}{2}$:
$$\ln 2 \ \ \approx \ \ \frac{1}{2} \ \ + \ \ \frac{1}{2}\cdot \frac{1}{4} \ \ + \ \ \frac{1}{3}\cdot\frac{1}{8} \ \ + \ \ \frac{1}{4}\cdot \frac{1}{16} \ \ + \ \ \frac{1}{k}\cdot\frac{1}{2^k} $$
The more terms you add, the better the approximation. For example
When $k=5$, we get $\ln 2 \approx 0.68854167$ which is off by $0.7\%$
When $k=10$, we get $\ln 2 \approx 0.69306486$ which is off by $0.01\%$
In reality, $\ln 2 = 0.69314718$ to 8 significant figures.

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I am delighted to learn that the pencil and paper algorithms are still taught, but you are wrong to say that square roots are hard to calculate by such methods. – Rob Arthan Mar 03 '16 at 23:20