Let $f(z)$ analytic. Prove that $\overline{ f(\bar{z})}$ is also analytic.
How do I use the concept of analytic of $f(z)$ here? any help
Let $f(z)$ analytic. Prove that $\overline{ f(\bar{z})}$ is also analytic.
How do I use the concept of analytic of $f(z)$ here? any help
Use the series expansion of $f$ around a point. If you conjugate $z$ first and then $f$, the coefficients are conjugated and you still have a series expansion around each point.
\overline{f(z)}
gives $\overline{f(z)}$. The\overline{}
command adapts to the length of the argument, so for example you can get $\overline{z_1+z_2+z_3+z_4}$ using\overline{z_1+z_2+z_3+z_4}
. – Pedro Jan 18 '16 at 19:34