I am an unconditional admirer of WolframAlpha and for this reason I want to let the people of this error (or is it really the fault of mine?). If I'm not mistaken, I would be very happy to contribute, communicating this default calculation, to this extraordinary and beneficial website.
I was watching something on the cubic curve $$y^2=x^3+7x+9$$ More precisely I was interested in integer points $(x, y)$ with both coordinates being prime numbers. I thought having in hand the point $ (5,\pm 13) $ but, consulting WolphramAlpha, his answer gives only the two points $(-1,\pm 1)$ and $(0,\pm 3)$
Maybe I need to rest a bit ...
Have a rest.
– Matthew Cassell Dec 19 '15 at 00:34Q<x> := PolynomialRing(Rationals());} E00 := EllipticCurve(x^3+7*x+9); Q00 := IntegralPoints(E00); Q00;
to the online calculator, one get $(x,y) = (-1,\pm 1), (0, \pm 3), (5, \pm 13), (17, \pm 71), (27,\pm 141)$. – achille hui Dec 19 '15 at 01:24Generators(E00)
to get the generators. – achille hui Jan 15 '16 at 15:08