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Let's assume $r < a < b < t$ , and a function $f:[r,t] \to \mathbb{R}$ , $f $ differentiable in $(r,t)$, with $f'(a)< 0 < f'(b)$ . Prove that there exists $c$ such that $a<c<b$ and $f'(c) = 0$

(So basically, i want to something like Bolzano for $f'$, although $f'$ may not be continuous)

Noa Even
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Alan
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