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By the definition of square root, we can take square root of $16$ as $\pm4$.

But in problems, why do we take $16^{\frac12}$ as $4$?

And also how can we say, if $a^m=b^n$ then $a=b^{m/n}$?

Because when we take $x^2=a$, we solve it as $x=\pm{a^{1/2}}$.

barak manos
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Muzamil
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1 Answers1

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We take square root of 16 as 4 only when a negative solution is not viable e.g. when you are counting the number of objects, an answer of '-4' will not make any sense and is ignored.