I'm being asked that for each of the following spaces $(X_i, T_i)$, find an open cover $U_i$ that does not contain a finite subcover.
$X_i$ is a set and $T_i$ is a collections of subsets.
I have come up with a few answers that seem too easy and are now causing me to doubt my interpretation of the question.
I interpreted it as: find an open conver $U_i$ that contains an infinite amount of subcovers.
Here are the spaces and my answers:
1) $X_a = \mathbb{R}$, $T_a = \left \{(-\infty,a) : a \in \mathbb{R} \cup \left \{ \pm \infty \right \} \right \}$
My answer is the open set $(-n,n)$
- it is open
- it covers the collections of sets given
- it contains infinitely many subcovers (i.e- (-1,1),(-2,2),...))
2) $ X_b = \mathbb{Q} \cap [0,1] $, $T_b = \left \{ U \cap [0,1] : U \subset \mathbb{R} \right \}$
Once again, my answer is $(-n,n)$ which seems to satisfy all conditions once again. For an open cover with finite subcovers I would have just picked $(-1,2)$
3) $ X_c = \left \{ x \in \mathbb{R} : 0 < \left \| x \right \| \leq 1 \right \}, T_c $ is the standard topology
Here, the set is a circle with radius 1, surrounding the centre point in 2 dimensions.
Assuming the standard topology is simply all open covers $U \subset \mathbb{R^2}$, my answer becomes $(n_1,-n_1),(n_2,-n_2)$ which seems to satisfy all conditions again.
Can someone correct me if I'm wrong and help lead me to a proper understanding of the question.
Thanks, Greg.
EDITED ANSWERS
1) $ \left \{ (- \infty , a ) : a \in \mathbb{R} \right \} $
2) $ \left \{ 0,1 \right \} \cup \left \{ (\frac{1}{n},1-\frac{1}{n}) : n \in \mathbb{N} \setminus \left \{ 1 \right \} \right \}$
3) $ \left \{ \left \{ x \in \mathbb{R^2}: 0 < ||x|| \leq (1 - \frac{1}{n}) \right \} : n \in \mathbb{N} \setminus \left \{ 1 \right \} \right \} $