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Can an interval on the real line, $(a,b)\subset \mathbb R$ be connected if its inf and sup are not part of the interval? Obviously if the inf and sup of the interval are not in the interval it cannot be a closed interval.

jessica
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1 Answers1

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$(1,2)$ is connected

$\sup(1,2) \notin (1,2)$

$\inf(1,2) \notin (1,2)$


Further reading:

Intervals are connected and the only connected sets in $\mathbb{R}$

https://proofwiki.org/wiki/Subset_of_Real_Numbers_is_Interval_iff_Connected

Set $A$ interval in $\mathbb{R}\implies$ connected

BCLC
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