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Show whether $F: \mathbb{R}^3 \rightarrow \mathbb{R}$ defines a normed vector space on $\mathbb{R}^3$.

For $(\underline{x}) = (x_1, x_2, x_3)$,

$F(\underline{x}) = (\sum_{i=1}^{3} |x_i|^\frac{1}{2})^2$.

So at first glance this seems similar to the Euclidean norm, only with the powers swapped over. However I'm fairly sure this contradicts the triangle inequality for norms but I'm not sure how to show this.

C.B.
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There's probably an even simpler example you can use, but this one works.

Consider the three points $(0,0,0)$, $(1,0,0)$ and $(2,2,2)$. Attempt to find the distances between them and apply the triangle inequality, and you should get something like $$1 + \left(1+2\sqrt{2}\right)^2\geq 18$$

or approximately

$$ 15.6 \geq 18$$

which is ridiculous.