Let $F$ be a field.
I already know that there is an algebraic closure $\overline{F}$ of $F$ which satisfy that every $f(x)\in \overline{F}[x]$ is splits in $\overline{F}[x]$.
Is there a smallest extension field $E$ of $F$ such that every $f(x)\in {\mathbf F}[x]$ is splits in $E[x]$?
Or such extension field $E$ must be the algebraic closure of $F$?