$$e^i = (e^i)^{(2\pi/2\pi)} = (e^{2\pi i})^{1/2\pi} = 1^{1/2\pi} = 1.$$
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3It is not true that $(z^a)^b=z^{ab}$ in general. If you search this site you will find thorough discussions of this fact. – Mariano Suárez-Álvarez Sep 12 '15 at 16:54
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They are taking the root of a complex number by writing $x^{1/2\pi}$. And it isn't even a rational root. But i am still not convinced :D. – MrYouMath Sep 12 '15 at 16:56