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$\lim_{n \rightarrow \infty } 2^{n} \sqrt{2-\sqrt{2+\sqrt{2+...+\sqrt{2}}}}$ where the 2 inside the roots appear n times. For example if n = 2 : $2^{2} \sqrt{2-\sqrt{2}}$ I discovered this. Has this been already developed/made before?

B2VSi
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1 Answers1

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Since $$\sqrt{2-\sqrt{2+\sqrt{2+\cdots+\sqrt{2}}}}$$ is the side length of the regular $2^{n+1}$-gon inscribed in a radius $1$ circle, the sum of the $2^{n+1}$ sides will converge to the circumference of that circle. Thus $$\lim_{n\rightarrow\infty}2^{n+1}\sqrt{2-\sqrt{2+\sqrt{2+\cdots+\sqrt{2}}}}=2\pi.$$

Eric Naslund
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