Throwing my hat into the ring: To begin with, the natural numbers represent the number line extended in the positive direction. They behave as we expect with respect to addition and subtraction:
The + operator is defined in such a way that if we have $a$ objects, and bring over another $b$ objects, then the quantity given by $a+b$ is how many objects we end up with.
The $\times$ operator is defined in such a way that if we have $a$ rows of $b$ objects each, then the quantity given by $a \times b$ is how many objects we have altogether.
We can extend the natural numbers into zero and the negative domain in a straightforward way (so that subtraction can be viewed as addition with negative numbers). We have to define multiplication in a way that confused some early mathematicians, but from our modern perspective, it is usually clear that it is the "natural" way to do it.
The integers have gaps in them—gaps that only become apparent if we try to measure continuous things (in some as-yet ill-defined sense) rather than count discrete things. That is to say, if we count apples, then the integers have no gaps that we can discern, but if we try to measure the length of a pencil, it may be more than $6$ inches but less than $7$.
The rationals are a first attempt to fill in these gaps. With them, we can say that a pencil is $6\frac{5}{8}$ inches long, and that (and the rationals in general) will be good enough for any practical purpose we like. The rationals complete the integers in the following sense: If you apply the operations $+, -, \times, \div$ in any finite combination (that does not involve division by zero) to the integers, you get the rationals. Nothing you do in that direction will ever yield anything that is not rational.
However, of course, people (by which I mean mathematicians) eventually became interested in numbers not only for their practical value, but for their own sake. Consider a square one unit on a side. Its diagonals are obviously longer than one unit, but shorter than two units. How long are they, exactly?
They are not integers, clearly, but as you surely know, they are not rationals, either. They are literally irrational—not expressible as the ratio of two integers. The reals (the rationals and irrationals together) therefore fill in gaps in the rationals in the same way that rationals fill in the gaps in the integers. They do this by extending those four operations $+, -, \times, \div$ to infinite combinations. For instance, the number $\sqrt{2}$ can be represented as
$$
\sqrt{2} = 1+\frac{4}{10}+\frac{1}{100}+\frac{4}{1000}+\frac{2}{10000}+\cdots
$$
where the ellipsis indicates that the addition and division operations extend to infinity in the appropriate way. That transition from finite to infinite is crucial.
There are, as you discovered, many ways to define/construct the reals, and so the question may arise: Which reals are the "real" reals? Fortunately, the problem resolves itself if we constrain ourselves to worrying only that the reals behave in the way that we expect them to—by adding, multiplying, and dividing as expected—because it turns out that each of the constructions of the reals are equivalent in that way.
One might despair, though, that once again, the reals have gaps in the same way that the integers and rationals did. That turns out not to be true: There are no numbers between reals that are not real themselves.
Of course, as you may well know, the reals have a gap in a different sense. We pointed out that if we take the integers and permit arithmetic to be performed on them, we end up with the reals. For instance, if we square any integer (or indeed, any real), we end up with another real. We can square any real. However, the reverse is not true: We cannot, by squaring any real, obtain a negative number. We therefore must introduce the imaginary and then the complex numbers. Those, at last, are complete in the sense of algebraic closure.