Are there numerical rounding issues in using the cubic formula to find roots of cubic equations? Similarly with the quartic formula?
I do know for the quadratic formula to solve $ax^2+bx+c = 0$ that you use the formulas $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ or $x = \frac{2c}{-b \mp \sqrt{b^2-4ac}}$ so that the numerator or denominator respectively are chosen so that they are the sum of two terms with the same sign.