I presume you want to do this algorithmically. In Mathematica:
Union[Sort /@ Tuples[{A, B, C}, 2]]
{{A, A}, {A, B}, {A, C}, {B, B}, {B, C}, {C, C}}
More generally:
myMultiSet[n_Integer, k_Integer] := Union[Sort /@ Tuples[Range[n], k]]
So for instance myMultiSet[5,3]
yields
{{1, 1, 1}, {1, 1, 2}, {1, 1, 3}, {1, 1, 4}, {1, 1, 5}, {1, 2, 2}, {1,
2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 3}, {1, 3, 4}, {1, 3, 5}, {1,
4, 4}, {1, 4, 5}, {1, 5, 5}, {2, 2, 2}, {2, 2, 3}, {2, 2, 4}, {2, 2,
5}, {2, 3, 3}, {2, 3, 4}, {2, 3, 5}, {2, 4, 4}, {2, 4, 5}, {2, 5,
5}, {3, 3, 3}, {3, 3, 4}, {3, 3, 5}, {3, 4, 4}, {3, 4, 5}, {3, 5,
5}, {4, 4, 4}, {4, 4, 5}, {4, 5, 5}, {5, 5, 5}}